10x^2+19x+10=0

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Solution for 10x^2+19x+10=0 equation:



10x^2+19x+10=0
a = 10; b = 19; c = +10;
Δ = b2-4ac
Δ = 192-4·10·10
Δ = -39
Delta is less than zero, so there is no solution for the equation

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